What is the best way to return a boolean when a negative value exists in a list?

I have the following funciton telling us that a series has at least one negative value:

def has_negative(series):
    v=False
    for i in range(len(series)):
        if series[i]<0:
            v=True
            break
    return v

When we use this function on an example we get :

y=[1,2,3,4,5,6,7,8,9]
z=[1,-2,3,4,5,6,7,8,9]

print(has_negative(y))
print(has_negative(y))

Output:

>>> False
>>> True

The function seems to work well, although I want to make it shorter, any suggestion from your side will be appreciated

>Solution :

You can utilise the built-in any function as follows:

def has_negative(lst):
    return any(e < 0 for e in lst)

print(has_negative([1,2,3,4,5,6,7,8,9]))
print(has_negative([1,-2,3,4,5,6,7,8,9]))

Output:

False
True

EDIT:

Did some timing tests based around this and other suggested answers. Whilst this is concise and functionally correct, it doesn’t perform well. Keep it simple and use @quamrana’s first suggestion – it’s much faster