What is the logic here for post increment?

#include<stdio.h>

int main()
{
    int x;
    int *ptr;
    ptr = &x;
    *ptr = 0;
    printf("x= %d\n", x);
    printf("*ptr= %d\n", *ptr);

    *ptr += 5;
    printf("x= %d\n", x);
    printf("*ptr= %d\n", *ptr);
 
    (*ptr)++;
    printf("x= %d\n", x);
    printf("*ptr= %d\n", *ptr);

    return 0;
}

Acc. to precedence brackets will be first simplified and then ++ and therefore it will be post increment :
(*ptr)++ (third portion of question)

value should be 5 as it is post increment operator i.e it will first assign the value and then increment..In this case also it should first assign value and then increment..But answer coming is
6

>Solution :

(*ptr)++; // increment the value (to 6)
// other stuff
printf( .... // print the value

The (post)-increment occurs substantially before the value is fetched to be printed.