What percentage of clients live between 1 & 3 miles

Tried code:

SELECT count(*) Count_people_inside_3miles
FROM CLIENT_DATA
WHERE (ABS(C_ADD_X) >=1 AND ABS(C_ADD_X) <=3) AND (ABS(C_ADD_Y) >=1 AND ABS(C_ADD_Y) <=3);

SELECT count(CLIENT_ID) Count_Total_people
FROM CLIENT_DATA;

Result:

How do I calculate 15/24*100?

>Solution :

SELECT
       CONVERT(VARCHAR(5), (COUNT_PEOPLE_INSIDE_3MILES / COUNT_TOTAL_PEOPLE) * 100) + '%' AS formatted_percentage
FROM (
  SELECT count(*) COUNT_PEOPLE_INSIDE_3MILES
  FROM CLIENT_DATA
  WHERE (ABS(C_ADD_X) >=1 AND ABS(C_ADD_X) <=3) AND (ABS(C_ADD_Y) >=1 AND ABS(C_ADD_Y) <=3)
) t1,
(
  SELECT count(CLIENT_ID) COUNT_TOTAL_PEOPLE
  FROM CLIENT_DATA
) t2;

This will calculate the percentage of people inside 3 miles and return the result in a column called percentage.