Why are the first set of characters only replaced?

From my last post, I’ve made some changes to my code so that it functions more smoothly; however, it won’t print what I expect. I’ve found out how to count the individual characters in the input, but when changing the consecutive characters to letters, it only prints the first set of consecutive characters. For example, 1 consecutive character = A, 2 = B, 3 = C… When I input *^^**&&&, the output is A and not ABBC. How could I fix this; there’s probably a simple fix again sorry.

encrypted=input("Enter an encrypted message: ")
count=1
length=""

if len(encrypted)>1:
    for i in range(1,len(encrypted)):
       if encrypted[i-1]==encrypted[i]:
          count+=1
       else :
           length += encrypted[i-1] + str(count)
           count=1
           
    length += encrypted[i] + str(count)
    
else:
    i=0
    length += encrypted[i] + str(count)

print(chr(count+64))

>Solution :

This does what you describe:

encrypted = input("Enter an encrypted message: ")

count = 0
result = ''
for i, ch in enumerate(encrypted):
    if i == 0 or ch == encrypted[i-1]:
        count += 1
    else:
        result += chr(count + 64)
        count = 1
if count > 0:
    result += chr(count + 64)

print(result)

Result:

Enter an encrypted message: @##$$%%%
ABBC

It doesn’t build up a record of what was found, adding that back in if you need it:

encrypted = input("Enter an encrypted message: ")

ch = ''
count = 0
result = ''
counts = []
for i, ch in enumerate(encrypted):
    if i == 0 or ch == encrypted[i-1]:
        count += 1
    else:
        result += chr(count + 64)
        counts.append((ch, count))
        count = 1
if count > 0:
    result += chr(count + 64)
    counts.append((ch, count))

print(result, counts)

But if you need it anyway, you may as well:

encrypted = input("Enter an encrypted message: ")

ch = ''
count = 0
counts = []
for i, ch in enumerate(encrypted):
    if i == 0 or ch == encrypted[i-1]:
        count += 1
    else:
        counts.append((ch, count))
        count = 1
if count > 0:
    counts.append((ch, count))

print([chr(count+64) for _, count in counts], counts)