Why can't I assign a member function pointer to an overloaded function without using a type alias?

See below example. Can’t think of a reason why this is not possible. Am I really forced to introduce a using decl or typedef? Any other reasonable workarounds?

struct Foo {
    public:
        int get_res() { return 1; }
        int get_res(int i) { return 1; }
};


// Works!
struct Accessor {
    using overload = int(Foo::*)();
    static constexpr overload resGetter = &Foo::get_res;
};

// error: expected unqualified-id before ')' token
struct Accessor {
    static constexpr int(Foo::*)() resGetter = &Foo::get_res;
};

>Solution :

struct Accessor2 {
    static constexpr int(Foo::*resGetter)() = &Foo::get_res;
};

That’s why you don’t usually write member function pointers like this — it looks strange, and people make errors.

Typedefs do not generate any code — you can use them as much as you want to make your code readable.