I saw on the internet and was told in uni, that you should specify array’s size, when declarin this way: int* array = new int(size);
Hovever, doesn’t this line simply apply a value to the address, that was created?
In other words,
(even further, than I should have, by logic)
Why so? Are dynamic arrays a good practice at all? They don’t seem reliable
as described above…
>Solution :
You have been told wrong, the correct way is
int* array = new int[size];
Use [] not ().
Your version allocates a single int not an array, and, as you have observed, initialises the integer to the given value.
In general new T[size] allocates an array of T of the given size, and calls the default T constructor for each element. Whereas new T(args, ...) allocates a single T and calls the T constructor with the given arguments.
On the final point, you should rarely use dynamic arrays in C++, almost always the correct thing to use in their place is a std::vector.