Why does not else: run when if is false?

var1 = float(input("Variable 1:"))
operator = input("Write your operator:")
if operator == "+" or "/" or "*" or "-" or "**":
    var2 = float(input("Variable 2:"))
    if operator == "+":  # Addition
        print(f"{var1} + {var2} = ")
        print(var1+var2)
    elif operator == "*":  # Multiplication
        print(f"{var1} * {var2} = ")
        print(var1 * var2)
    elif operator == "/":  # Division
        print(f"{var1} / {var2} = ")
        print(var1/var2)
    elif operator == "-":  # Subtraction
        print(f"{var1} - {var2} = ")
        print(var1 - var2)
    elif operator == "**":  # Power
        print(f"{var1} ** {var2} = ")
        print(var1 ** var2)
else:
    print("Invalid operation, enter a correct operator")

I have just started to programme in Python and I have decided to create a calculator that does basic mathematical operations. It is supossed to work correctly when I put the correct symbol into the "operator" variable, but when I put some random letter it does not run the command "else". Why does this happen?

>Solution :

You’re applying the wrong logic in the code

operator == "+" or "/" or "*" or "-" or "**" is just comparing operator and + symbol, Ignoring rest operators

Correct way is

if operator == "+" or operator == "-" or operator == "*" or operator == "/" or operator = "**

I’ll implement this like

if operator in ("+", "-", "*", "/", "**")