Why does the HTML code after the PHP block not display?

<div class="texts">
        <div class="text">
            <p>Test paragraph</p>
        </div>
        <?php
            require_once 'twitterdblogin.php';
            $connection = new mysqli($hn, $un, $pw, $db);

            if ($connection->connect_error) die ("Fatal error.");

            $query = 'SELECT * FROM `TWEETS`';
            $result = $connection->query($query);
            if (!$result) die("Fatal error");

            $rows = $result->num_rows;

            for ($j = 0; $j < $rows; $j++) {
                $result->data_seek($j);

                echo '<div class="text">'.htmlspecialchars($result->fetch_assoc()['text']).'<div>';
            }

            $result->close();
            $connection->close();
        ?>
        <div class="text">
            <p>Test paragraph</p>
        </div><div class="text">
            <p>Test paragraph</p>
        </div>
    </div>

The first "text" div container displays and so does the PHP block successfully, but every HTML code after the PHP block does not display. I have tried entering including an exit(0) function at the end of the script — but to no success.

>Solution :

That because you made a mistake in the line:

$result = $connnection->query($query);

Replace it with the next one:

$result = $connection->query($query);

The second one. Instead of echo

echo '<div class="text">'.htmlspecialchars($result->fetch_assoc()['text']).'<div>';

should be

echo '<div class="text">'.htmlspecialchars($result->fetch_assoc()['text']).'</div>';

You’ve missed a slash.

These mistakes break the code execution and cause that behaviour.