Why does "xxx::function();" not work but "using namespace xxx; function();" does?

I am using the boost graph C++ library and I stumbled over a problem when asking for the number of vertices of a grid graph:

The following code snipped creates a 2 dimensional grid graph of shape 5 by 6 and then prints the number of vertices of that graph which is 5×6 = 30.
However, this does not compile with the error error: ‘num_vertices’ is not a member of ‘boost’.

#include <boost/graph/grid_graph.hpp>
#include <iostream>


int main()
{
    typedef boost::grid_graph<2> Graph;
    Graph g({5, 6});
    std::cout << "Num vertices: " << boost::num_vertices(g) << std::endl;

    return 0;
}

If I change the code to by writing using namespace boost; at the beginning, then it does work:

#include <boost/graph/grid_graph.hpp>
#include <iostream>

using namespace boost;

int main()
{
    typedef grid_graph<2> Graph;
    Graph g({5, 6});
    std::cout << "Num vertices: " << num_vertices(g) << std::endl;

    return 0;
}

Curiously this is not a problem when I use a different boost graph type like boost::adjacency_list<>.

So I have three questions:

1. Which operating principle of namespaces causes this behavior?
2. Regarding the special case of the grid graph implementation in boost: Is this a bug or is this intended behavior?
3. Is there any way I can call the num_vertices function without the using directive?

>Solution :

According to https://www.boost.org/doc/libs/1_82_0/libs/graph/doc/VertexListGraph.html, this function must be called as num_vertices(g).

It is probably implemented as a "hidden friend function", meaning it can only be found via argument-dependent lookup.