Write a function that displays the corresponding letter grade

January 25, 2022

I’m supposed to make a user-defined function that will print the letter grade of the following mark range (ex: 99-100 = A+), but when I execute the code, it functions properly except it prints the number 1 on a new line.

Example Input:
Please input your grade in ICT:
99

Example Output:
A+
1

#include <iostream>

using namespace std;

void gr(char);
void gr2(char, char);

int main() {
    int grade;
    
    cout << "Please input your grade in ICT:" << endl;
    cin >> grade;
    
    if(grade >= 99 && grade <= 100){
        gr2('A', '+');
    }
    
    else if(grade >= 95 && grade <= 98){
        gr2('A', '-');
    }
    
    else if(grade >= 90 && grade <= 94){
        gr('A');
    }
    
    else if(grade >= 85 && grade <= 89){
        gr2('B', '+');
    }
    
    else if(grade >= 81 && grade <= 84){
        gr2('B', '-');
    }
    
    else if(grade >= 75 && grade <= 80){
        gr('B');
    }
    
    else if(grade >= 71 && grade <= 74){
        gr('C');
    }
    
    else if(grade >= 61 && grade <= 70){
        gr('D');
    }
    
    else{
        gr('F');
    }
    
    cout << gr;
    
  return 0;  
    
}

void gr(char a){
    int gr;
    cout << a << endl;

}

void gr2(char a, char b){
    
    int gr2;
    cout << a << b << endl;
}