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Write a function that should return a new string, containing only the words that don't have the letter "e" in them in javascript

byMR

October 1, 2022

what am I doing wrong in the code that I mentioned below?

My outputs are [ ‘What’, ‘time’, ‘is’, ‘it’, ‘everyone?’ ] and [ ‘building’ ]. These outputs should be string because I used join method. Also the first output is totally wrong.

let removeEWords = function(sentence) {
  debugger
  let arrayedSentence = sentence.split(" ");
  let newArr = [];
  return arrayedSentence.filter(function(el) {
    if (!el.includes("e")) {
      newArr.push(el);
    }
    return newArr.join(" ");
  })

};
console.log(removeEWords('What time is it everyone?')); // 'What is it'
console.log(removeEWords('Enter the building')); // 'building'

>Solution :

You need to ‘filter’ and not add to an array – you are using filter as a forEach

const removeEWords = sentence => sentence
  .split(" ")
  .filter(word => !word.includes("e")) // this returns true to return or false to drop
  .join(" ");
console.log(removeEWords('What time is it everyone?')); // 'What is it'
console.log(removeEWords('Enter the building')); // 'building'