XPath : Contains() on a xml to find urls, but it actually find more

I’m trying to find the correct XPath expression to get only urls from all my documents, whatever the tag is. I’m trying with this one :

<urlset xmlns="https://www.sitemaps.org/schemas/sitemap/0.9">
  <url>
    <loc>https://url
    </loc>
    <lastmod>2019-08-07T15:01:51+00:00
    </lastmod>
  </url>
</urlset>

The following expression gives me these results :

//*[contains(.,’http’)]//text()

https://url

2019-08-07T15:01:51+00:00

What I’m looking for is to get rid of the second line. I need to be able to get only urls from any xml file.

>Solution :

Well, let’s ignore the fact that not all URLs contain "http" and not everything that contains "http" is a URL…

To find all text nodes containing "http", just use //text()[contains(., 'http')].

Or you could find