cannot understand logic of recursion

This function has to return reversed string. For example, “dog” -> “god”.
It works correctly but I don’t understand the logic and I need explanation

function reverse (str) {
   if (str.length <= 1) return str;
   return reverse(str.slice(1)) + str[0]
}

>Solution :

Explaination

Firstly, you call reverse(“dog”) and it return reverse(“og”)+”d”
Then the reverse(“og”) continue to run again. It returns reverse(“g”)+”o”
The last one, reverse(“g”) only returns “g” since the if statement is true

Then you plug the reverse(“g”) to the reverse(“g”)+”o”, as a result “go” is returned
Finally, plug reverse(“og”) to reverse(“og”)+”d”, which is “go”+”d”, as a result “god” is the output

The flow

• (1) reverse("dog") called -> return reverse("og")+"d"
• (2) reverse("og") called -> return reverse("g")+"o"
• (3) reverse("g") called -> return "g" (if statement)
• (4) plug (3) to (2) -> return "g" + "o" -> "go"
• (5) plug (4) to (1) -> return "go" + "d" -> "god"