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Convert to matrix but keep one diagonal to NULL in R

I have a huge dataset and that look like this.
To save some memory I want to calculate the pairwise distance but leave the
upper diagonal of the matrix to NULL.

library(tidyverse)
library(stringdist)
#> 
#> Attaching package: 'stringdist'
#> The following object is masked from 'package:tidyr':
#> 
#>     extract

df3 <- tibble(fruits=c("apple","banana","ananas","apple","ananas","apple","ananas"),
              position=c("135","135","135","136","137","138","138"), 
              counts = c(100,200,100,30,40,50,100))

stringdistmatrix(df3$fruits, method=c("osa"), nthread = 4) %>% 
  as.matrix()
#>   1 2 3 4 5 6 7
#> 1 0 5 5 0 5 0 5
#> 2 5 0 2 5 2 5 2
#> 3 5 2 0 5 0 5 0
#> 4 0 5 5 0 5 0 5
#> 5 5 2 0 5 0 5 0
#> 6 0 5 5 0 5 0 5
#> 7 5 2 0 5 0 5 0

Created on 2022-03-01 by the reprex package (v2.0.1)

However when I convert my stringdistmatrix to matrix (This step is essential for me),
my upper diagonal get filled with numbers.

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Is there anyway to convert to matrix but keep upper diagonal to NULL and save memory?

I want my data to look like this

  1 2 3 4 5 6
2 5          
3 5 2        
4 0 5 5      
5 5 2 0 5    
6 0 5 5 0 5  
7 5 2 0 5 0 5

>Solution :

I think you may need to use sparse matrices. Package Matrix has such a possibility. You can learn more about sparse matrices at: Sparse matrix

library(Matrix)

m <- sparseMatrix(i = c(1:3, 2:3, 3), j=c(1:3,1:2, 1), x = 1, triangular = T)

m

#> 3 x 3 sparse Matrix of class "dtCMatrix"
#>           
#> [1,] 1 . .
#> [2,] 1 1 .
#> [3,] 1 1 1

I suspect, however, that @Maël ‘s solution may be the best for relatively small matrices:

library(tidyverse)
library(stringdist)

mat <- stringdistmatrix(df3$fruits, method=c("osa"), nthread = 4) %>% 
  as.matrix() 

mat2 <- mat[!lower.tri(mat)] <- NA

object.size(mat)
#> 1792 bytes
object.size(mat2)
#> 56 bytes

Anyway, @LDT, you can try declare your matrices using both ways and then you can use function object.size to evaluate which way is less memory consuming.

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