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Counting number of elements less than and adding it to the original in Python

September 24, 2022

I have two lists I1 and I2. I am comparing elements of I2 to elements in I1 and want to add the number of elements which are less than or equal to it. For example, 11 in I2 has two two elements less than or equal to it in I1. Hence, 2 should be added to 11. Similarly, for elements 27 and 41 in I2. I present the current and expected output.

I1=[1,11,13,16,26,30,43,46]

I2=[11,27,41]
I2=[i for i in I2 if I2<=I1]
print("I2 =",I2)

The current output is

I2 = []

The expected output is

I2 = [13,32,47]

>Solution :

use a counter to see the number and their frequency which is less than current, so to avoid the repetiiton calculation

from collections import Counter

I1=[1,11,13,16,26,30,43,46]
I2=[11,27,41]

c1 = Counter(I1)
result = []

for i in I2:
    val = sum(j for v, j in c1.items() if v<=i) + i
    result.append(val)
print(result) # 13 32 47