How do I divide by the corresponding element in the list while using zip()

I am trying to find out how can I do (i1+i2)/[i] for the ith element before getting the mean.

import numpy as np

def avg_prod(l1, l2):
    np.mean([i1 * i2 for i1, i2 in zip(l1, l2)])

I tried to use i inside the code, but it produces an error.

>Solution :

You can use enumerate:

def avg_prod(l1, l2):
    np.mean([i1 * i2 / i for i, (i1, i2) in enumerate(zip(l1, l2))])

or iterate over indices:

def avg_prod(l1, l2):
    np.mean([l1[i] * l2[i] / i for i in range(min(len(l1), len(l2)))])

you can minimize it in case you are sure that the lengths of the lists are equal:

def avg_prod(l1, l2):
    np.mean([l1[i] * l2[i] / i for i in range(len(l1))])