Create a dictionary based on a function and a list of strings

August 4, 2022

I have a list of strings, lostrings, and a function, splitter, which splits a string.

lostrings = 
    ['308 921 q53 C13 0000000200',
     '300 920 q51 C13 000000199',
     '318 921 q53 C12 0000000199']

def slitter(s: str) -> list:
    value1 = s[:3]
    value2 = s[4:7]
    value3 = s[9:12]
    value4 = s[14:17]
    value5 = s[25:]
    return [value1, value2, value3, value4, value5]

Example: splitter(lostrings[0]) will output ['308', '921', 'q53', 'C13', '200'].

What I am trying to do is to create a key-value dictionary where keys are 'value1, 'value2', 'value3', 'value4', 'value5' and values are lists. Desired output is as follows:

{'value1': ['308', '300', '318'],
 'value2': ['912', '920', '921'],
 'value3': ['q53', 'q51', 'q53'],
 'value4': ['C13', 'C13', 'C12'],
 'value5': ['200', '199', '199']}

I tried the following:
1.

dict(zip(['value1', 'value2', 'value3', 'value4', 'value5'], [splitter[lostrings[row]] for row in range(len(lostrings))]))

This does not give the correct output. I am not sure how to create a dictionary of 'str':list out of a list of strings based on a function.

>Solution :

You can map the list of strings to the splitter function, transpose the output so that the lists align with the keys, which you can then zip together to construct a dict:

dict(
    zip(
        ['value1', 'value2', 'value3', 'value4', 'value5'],
        map(
            list,
            zip(*map(splitter, lostrings))
        )
    )
)

Demo: https://replit.com/@blhsing/OutstandingWeakGnudebugger#main.py