Create list of arrays that contain specific element

I need to create a function that searches if certain string is within an array and create a list with all the elements (lists) that contain it. For example:

word = 'busy'
array = [[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']],[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]]

So my output should be:

[['99', 'Normal', [], ['busy', '0'], 362.01, 'working', '1']]

But I only get that the validation that says that the string doesn’t exist, when it obviously does. Here’s the code:

array = [[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']],[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]]

def searchBusyWorkers(array):
    busy = []
    for x in array:
        if 'busy' in x:
            ind = x.index('busy')
            busy.append(array[ind])
            return busy
        else:
            return "No workers have that condition."

>Solution :

Try This

word = 'busy'
array = [[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']],
[['F27', 'Normal', [], ['free', '0'], 28016.537865230806, 'working', '1']]]


def searchBusyWorkers(array,word):
    out = []
    for a in array:
        for i in a:
            for x in i:
                try:
                    if word in x:
                        out.append(i)
                except TypeError:
                    if word == x:
                        out.append(i)
    if out:
        return out
    return "No workers have that condition."

print(searchBusyWorkers(array,word))

OUTPUT

[['99', 'Normal', [], ['busy', '0'], 28016.2, 'working', '1']]