Filter function with 2 array sets

January 25, 2022

I am trying to achieve the same result as i wrote in below syntax by implementing filter function to my script.

The current script i have

    let sheet = [
        { $0: { 'Name': 'Report1' } },
        { $0: { 'Name': 'Row Count' } },
        { $0: { 'Name': 'Report2' } },
        { $0: { 'Name': 'User' } }
    ]

    let nope = ['User','Row Count','Container']
    let result = []

    for(let i = 0; i < sheet.length ;i++){
        if(sheet[i].$0.Name != nope[0] && sheet[i].$0.Name != nope[1] && sheet[i].$0.Name != nope[2]){
            result.push(sheet[i])
        }
    }
    
    console.log(result)

On my browser inspect element, it will result of (2) [{…}, {…}] on console.log

I tried using filter function

    let result_2 = sheet.filter(w => !w.$0.Name.includes(nope[0]))
    console.log(result_2)

1 : One problem and logic i face is that im unsure on how can i includes all the element of ‘nope’ in ‘includes()’
2 : I will have to hard code the index such as nope[0] which i dont think is advisable if its going to be a big array

>Solution :

You actually almost finish but you reverse the w.$0.Name and nope.

let sheet = [
    { $0: { Name: "Report1" } },
    { $0: { Name: "Row Count" } },
    { $0: { Name: "Report2" } },
    { $0: { Name: "User" } },
];

let nope = ["User", "Row Count", "Container"];

let result_2 = sheet.filter(w => !nope.includes(w.$0.Name));

console.log(result_2);

PS: I think you should take a break and drink a tea. 🙂