On my web page are two different type of errors.
The first one is:
<div class="warning" data-text="text-field-error" dir="ltr">Diese ID ist nicht verfügbar.</div>
And the second one is:
<div class="separator-notice text-notice text-margin theme-noticeerror-font" dir="ltr">Bei der Verbindung zum Server ist eine Zeitüberschreitung aufgetreten.</div>
for example if I try wrong email it doesnt have a specific value how often you can repeat. From time to time its diferent. Now the first error means that this email (in my case ID) isnt valid.
The second errors meaning is that the Server connection has failed.
Now with selenium I want to handle these two different errors something like this:
for line in lines:
driver.find_element_by_id(input_id).send_keys(line)
driver.find_element_by_class_name(check_available).click()
count += 1
time.sleep(1)
try:
# Check if I get error one
except:
# I got an error two
else:
pass
Ive already looked around at stack but couldnt find anything that matches my requirements.
I also have tried it with xpath by text like this:
try:
driver.find_element_by_xpath("//div[contains(text(), ' Diese ID ist nicht verfügbar.')]")
except:
# It has to be error two
So now is my question:
How can i check which error i currently have and how can i work with that error. For example
if error1:
print("error_one")
if error2:
print("error_two")
>Solution :
You can do that even without try – except at all.
You can do something like this:
for line in lines:
driver.find_element_by_id(input_id).send_keys(line)
driver.find_element_by_class_name(check_available).click()
count += 1
time.sleep(1)
first = driver.find_elements_by_xpath("//div[contains(text(), 'Diese ID ist nicht verfügbar.')]")
second = driver.find_elements_by_xpath("//div[contains(text(), 'Bei der Verbindung zum Server ist eine Zeitüberschreitung aufgetreten')]")
if first:
#you have got the first notification
if second:
#you have got the second notification
You can also do this with the expected conditions and with try – except, but this approach looks to be the simplest.