addition(int a) => (int b) => (int c) => a+b+c;
This is the function which returns dynamic for now
when I call addition(1)(2)(3) it prints 6 that’s fine
I want to know the exact return type of this function
I am trying out the currying concept!!
>Solution :
As Rahul say’s, the current type, of the returned value, in your example would be dynamic. But if we want to apply a static know type it would be something like:
int Function(int) Function(int) addition(int a) =>
(int b) => (int c) => a + b + c;
void main() {
print(addition.runtimeType);
// (int) => (int) => (int) => int
}