Call function with a parameter from another function

I have a function that repeatedly calls another function.

The second function has a bool parameter that changes the way it behaves, so when I call the first function I want to have a parameter that specifies the way the second function behaves.

void Function1(int n, bool differentBehavior = false)
{
    int a = Function2(n, differentBehavior);
    int b = Function2(1, differentBehavior);
    int c = Function2(2, differentBehavior);

    return a + b + c;
}

int Function2(int x, bool differentBehavior)
{
     if (!differentBehavior) // do something
     else // do something else
 }

The code itself is obviously an example (in reality the second function is called over 20 times and for code readability I would love to not have to specify the second parameter every time), but I put it there to explain what I’m currently doing. Is there no better way to achieve this?

>Solution :

You can introduce a local function to capture the second argument like so:

int Function1(int n, bool differentBehavior = false)
{
    int func(int n) => Function2(n, differentBehavior);

    int a = func(n);
    int b = func(1);
    int c = func(2);

    return a + b + c;
}

This is called "partial function application". See more here:

https://codeblog.jonskeet.uk/2012/01/30/currying-vs-partial-function-application/