How to break the program after my time completed in python?

April 14, 2022

I have a program to stop the for loop, even though the loop is running. I want to exit from this loop once my timer is over.

Ex: Timer set to = 10 seconds

def Start_function():
    timer = 10 seconds
    for i in range(60):
      print(i)
      time.sleep(1)
    return

Here loop will continue executing till for loop completion. But I need to exit from this function once the time is reached 10 seconds.

please help me out on this program.
Thanks in advance.

Find the below program:

import threading import time def demo(): print("Start function\n") for i in range(60):  print(i, end=" ") time.sleep(1) def thread_cancel(): time.sleep(5)
timer.cancel()
print("Yes ") timer = threading.Timer(1, gfg) timer.start() print("Cancelling timer\n") thread_cancel()  print("Exit\n")

>Solution :

You can simply add an if condition to check if i == timer: and then return to terminate the program.

import time
def Start_function():
    timer = 10
    for i in range(60):
        if i == timer:
            return "Timer ran successfully"
        print(i)
        time.sleep(1)

Output:

0
1
2
3
4
5
6
7
8
9
'Timer ran successfully'

But this is a bad implementation of a timer. You can improve by:

def Start_function(timer):
    for i in range(timer):
        time.sleep(1)
        print(i)

Start_function(10) # This starts the timer for 10 second