how to execute a function in a file in pymodule

This is an official py03 example.

Python::with_gil(|py| -> PyResult<Py<PyAny>> {
   let py_app = include_str!(concat!(env!("CARGO_MANIFEST_DIR"), "/app.py"));
   let app: Py<PyAny> = PyModule::from_code(py, py_app, "", "")?
        .getattr("test_function")?
        .into();
    app.call0(py)
})

my local app.py contains the following where the import is the rust module:

import GQLwrapper

print("running app.py")
def test_function:
   print("running test function")

The rust call is running the file and ‘running app.py’ is printed but the test function itself is not being called?

>Solution :

let app: Py<PyAny> = PyModule::from_code(py, py_app, "", "")?
    .getattr("test_function")?
    .into();

is like python code

import app
app.test_function

That doesn’t execute the function. Instead, you should use call_method0

let app: Py<PyAny> = PyModule::from_code(py, py_app, "", "")?
    .call_method0("test_function")?
    .into();