How to extract dates based on months using regex

import re

pattern = ['[\d]{1,2} [ADFJMNOS]\w* [\d]{2,4}','\d{1,2}/\d{1,2}/\d{2,4}']

text = "He welcomed me on 12 Jan 2014 and there by 15 OF 16 cakes for the party. Next morning on 16/05/2022 he waked up. He attended on 16 Feb 1966"

for i in pattern:
    temp_list = re.findall(i,text)
    print(temp_list)

Required output: 
['12 Jan 2014','16 Feb 1966']
['16/05/2022']

The output is coming with 15 OF 16. Is there any solution to get only the dates with months

>Solution :

Reverse the order of findall arguments and ensure correct escaping. (?:) avoids capturing the group.

patterns = [
    r"\d{1,2} (?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) \d{1,4}",
    r"\d{1,2}/\d{1,2}/\d{2,4}",
]

for pattern in patterns:
    matches = re.findall(pattern, text)
    print(matches)

Output:

['12 Jan 2014', '16 Feb 1966']
['16/05/2022']