Regex to match pattern of two digit number before a string

I have a text as so:

text = "There is 18 years of experience in marketing, with 5 years in sales."

I want to create a regex rule that will extract \d\d + "years" so that it may extract any one and two digit number followed by the keyword ‘years’ or ‘Years’ or ‘Yrs’ from any corpus.

Expected output: ["18 year", "5 years"]

I tried

text = re.findall(r'\d\d +years', text)

which returned None

How to get this?

>Solution :

Try this pattern: \d{1,2} (?:yrs|years?) with flag IGNORECASE in python.

See Regex Demo

Explanation

• \d{1,2}: capture one or two-digit.
• (?:: is a non-captured group.
• yrs|years: this captures "yrs" or "years". (case-insensitive)
• ?: this after "y" means "s" can be or not.