How to get id from dictionary where value is the same as the one I want?

    data =
{ "skusToId": [
        {
            "skus": [
                "SKU321",
                "SKU618",
                "SKU1443"
            ],
            "id": 0
        },
        {
            "skus": [
                "SKU1874"
            ],
            "id": 1
        },
        {
            "skus": [
                "SKU9322",
                "SKU9097",
                "SKU978" ,
                "SKU321"
            ],
            "id": 2
        }
}

lets say I have a list of skus, something like:

sku_list = [SKU321, SKU1443, SKU1874]
I would like to know how to get the ids where I find that sku. Note that a SKU can be found in multiple ids. Like SKU321.

What I’m trying is: by using

for elem in sku_list:
   foo = [v['id'] for v in data if data['skus'] == elem][0]
   print(foo)  

but this only returns me:

KeyError: 'skus'

where in fact I need something like alist of ids where I can find that SKU.

>Solution :

Depending on what you want you output to be

Just a check

sku_list = ['SKU321', 'SKU1443', 'SKU1874']
for obj in data['skusToId']:
   print(obj , any(map(lambda e: e in obj['skus'], sku_list)) )

which skus

 for obj in data['skusToId']:
     print(obj['id'], [e for e in obj['skus'] if e in sku_list] )

0 ['SKU321', 'SKU1443']
1 ['SKU1874']
2 ['SKU321']