how to pass argument to child function in js

August 11, 2022

function checkSalary(baseSalary, bonus, tax) {
    console.log(baseSalary, bonus, tax)
    function salary(baseSalary, bonus) {
        console.log(baseSalary, bonus)
        return baseSalary + bonus;
    }
    function salary_with_tax(tax) {
        console.log(tax)

        return salary() - tax;
    }
}

console.log(checkSalary(5000, 3000, 100))

I want to check using salary() and salary_with_tax() but don’t know how to pass the arguments.

>Solution :

You must call your inner functions at some point. Something like this:

I had to make some assumptions about what you want. I returned an object with the results of each inner function.

function checkSalary(baseSalary, bonus, tax) {
    console.log(baseSalary, bonus, tax)
    function salary(baseSalary, bonus) {
        console.log(baseSalary, bonus)
        return baseSalary + bonus;
    }
    function salary_with_tax(tax) {
        console.log(tax)

        return salary(baseSalary, bonus) - tax;
    }
    
    return {
      salary: salary(baseSalary, bonus),
      tax: salary_with_tax(tax)
    }
}

console.log(checkSalary(5000, 3000, 100))