How to return queryselector and queryselectorall in one function?

I am using functions get() and getall() to shorten query selector and query selector all.

const get = (target) => {document.querySelector(target)}
const getAll = (target) => {document.querySelectorAll(target)};

I wanted to fix this code as a function, so I was going to examine the element and create a function get() that return querySelectorAll if there are multiple elements of the same element and return querySelector if not.

So I made the code written below.

 const get = (target) => {
    if (NodeList.prototype.isPrototypeOf(target)) {
      return document.querySelectorAll(target)
    } else {
      return document.querySelector(target)
    }
  }

  console.log(get('div'));

const get = (target) => {
    if(target, target.length > 1) {
      return document.querySelectorAll(target);
    }else{
      return document.querySelector(target)
    }
  }

  const get = (target) => {
    if(typeof(target) == 'object') {
      return document.querySelectorAll(target);
    }else{
      return document.querySelector(target)
    }
  } 

However, all of the above codes do not work.
Type of target is string when entering the function.

>Solution :

Simply check the length of the result of document.querySelectorAll.

const get = (target) => {
    const els = document.querySelectorAll(target);
    return els.length > 1 ? els : els[0];
}