I am trying to convert an integer to a hexadecimal number according to the format

Through the code for i in range(2000,50000) I want to output the numbers from 2000 to 50000 in the following string format:

when i = 2000
output : 07 D0
When i = 50000
output : C3 50

How can I do that?

>Solution :

You can try this way:

def format_hex(number):
    # convert to hex string
    hex_str = hex(number)

    # upper case
    hex_str_upper = hex_str.upper()

    # format 
    hex_value = hex_str_upper[2:]
    if len(hex_value)==3:
        hex_value = '0' + hex_value
    hex_value_output = hex_value[:2] + ' ' + hex_value[2:]

    return hex_value_output