If statement always run in Python with openpyxl, even if it's false

I have never used if or else statements in python, and I can’t solve this easy problem:

from openpyxl import Workbook, load_workbook
from openpyxl.styles import PatternFill

wb = load_workbook("variables.xlsx")
ws = wb.active

if "A1" != "nameVariable":
    ws.append(["nameVariable", "value"])
    ws["A1"].fill = PatternFill("solid", start_color="FFA500")
    ws["B1"].fill = PatternFill("solid", start_color="FFA500")

It just fills the cell, but I don’t want it, bacause then this happens:
enter image description here
Also, does anybody knows why it doesn’t print in row 2?
Thanks in advice!

>Solution :

You are comparing the string "A1" and the string "nameVariable". To compare the content of the cell, use:

if ws["A1"].value != "nameVariable":