if statement, going back and forth

i am new to python, but have programmed some structured text, and a tiny bit c++
now i am working on a problem using if statements and it doesnt seem to work the way i am used to

example code:

more_guests = 0
loop = bool; loop = False
ferdig = int; ferdig = 1
while loop == False:
    guests = []
    more_guests = 0
    if int(ferdig) == 1:
        guest = input("type in guest ")
        more_guests = int(input("done? 1 for yes 2 for no "))
        if int(more_guests) == 1:
          guests.append(guest)
          ferdig == 3
        elif int(more_guests) == 2:
            guests.append(guest)
            ferdig == 2
        else:
            print("unvalid answer, please use 1 or 2")
            ferdig == 1
    elif int(ferdig) == 2:
        ferdig = 1
    elif int(ferdig) == 3:
        print(guests)
    else:
        loop = True

ive tried making sure its an integer and so on, just keep getting stuck on done? 1 for yes 2 for no, it always loop me back to type in guest

while using structured text i often used this way of going back and forth, but i cant seem to understand it in python, maybe i should rather use case/switch?
anyways if anyone could help me understand if you can use the IF statement this way in python is highly appreciated

>Solution :

I think you wrote wrong operator.
ferdig == 1 just comparing value operator. So it’s return true(1) or false(0).

if you wnat to change the ferdig’s value you should write ferdig = 3 in if statement.