Follow

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use
Contact

Join JSON String

Is there a particular way to join each individual block of string with | that way it’s

9000234|Test NPC|0|0|0|0|0|0|0|0| excluding isEnabled. I don’t want the other block merging with each other either. I’m not exactly sure how I would go about this.

    "100_npc": {
        "uniqueId": 9000234,
        "username": "Test NPC",
        "itemsObj": {"colour": 0, "head": 0, "face": 0, "body": 0, "neck": 0, "hand": 0, "feet": 0, "flag": 0, "photo": 0},
        "isEnabled": true
    },
    "101_npc": {
        "uniqueId": 9000251,
        "username": "Pelican",
        "itemsObj": {"colour": 0, "head": 0, "face": 0, "body": 0, "neck": 0, "hand": 0, "feet": 0, "flag": 0, "photo": 0},
        "isEnabled": true
    }
}

MEDevel.com: Open-source for Healthcare and Education

Collecting and validating open-source software for healthcare, education, enterprise, development, medical imaging, medical records, and digital pathology.

Visit Medevel

>Solution :

This seems to output what you are asking for: (playground)

    let data = {
      '100_npc': {
        uniqueId: 9000234,
        username: 'Test NPC',
        itemsObj: {
          colour: 0,
          head: 0,
          face: 0,
          body: 0,
          neck: 0,
          hand: 0,
          feet: 0,
          flag: 0,
          photo: 0,
        },
        isEnabled: true,
      },
      '101_npc': {
        uniqueId: 9000251,
        username: 'Pelican',
        itemsObj: {
          colour: 0,
          head: 0,
          face: 0,
          body: 0,
          neck: 0,
          hand: 0,
          feet: 0,
          flag: 0,
          photo: 0,
        },
        isEnabled: true,
      },
    };
    
    let result = [];
    
    for (let key in data) {
      if (data.hasOwnProperty(key)) {
        let item = data[key];
        let arr = [item.uniqueId, item.username];
        for (let objKey in item.itemsObj) {
          arr.push(item.itemsObj[objKey]);
        }
        result.push(arr.join('|'));
      }
    }
    
    console.log(result.join('\n'));
Add a comment

Leave a Reply

Keep Up to Date with the Most Important News

By pressing the Subscribe button, you confirm that you have read and are agreeing to our Privacy Policy and Terms of Use

Discover more from Dev solutions

Subscribe now to keep reading and get access to the full archive.

Continue reading