Say there is a list:
List = [["A", "A", "A", "A", "B", "B", "B", "B"],
["C", "C", "D", "D", "C", "C", "D", "D"],
["E", "F", "E", "F", "E", "F", "E", "F"]]
i want to join each of the first, second, and third element to a new list, so the new list will look like this:
NewList = ["ACE", "ACF", "ADE", "ADF", "BCE", "BCF", "BDE", "BDF"]
The problem is, it’ll only work if I know how much list are in the "parent" list, in this case it has 3 element.
I want them to join the like this
for i in range(8):
NewList.append(List[0][i] + List[1][i] + List[2][1] + ... List[n][i]
>Solution :
The zip() function is what you need
It allows two equal-size lists to be "zipped up" with element 0 of the first list being brought in alongside element 0 of the second, element 1 with element 1, etc.
It also works with multiple lists, more than 2.
You can use the * operator usefully here
It extracts the various separate lists from List
A list comprehension can do all your work for you
@python_user shows a brilliant solution above:
NewList = [''.join(one_list) for one_list in zip(*List)]