Keep items with same keys in two dictionary and discard other items

I am trying to remove all non-matching items (values with different keys) in two dicts dict_a and dict_b. What is a better way of achieving this?

Example:

d1 = {key1: x1, key2: y1, key4: z1}
d2 = {key1: x2, key3: y2, key4: w1}
# becomes:
# d1 = {key1: x1, key4: z1}
# d2 = {key1: x2, key4: w1}

My attempt:

keep_keys = [keyA for keyA in dict_a.keys() if keyA in dict_b.keys()]

for i in dict_b.copy().keys():
    if i not in keep_keys:
        del dict_b[i]

for i in dict_a.copy().keys():
    if i not in keep_keys:
        del dict_a[i]

I am looking for shorter (pythonic) way of doing this.

>Solution :

You can do:

d1 = {"key1": "x1", "key2": "y1", "key4": "z1"}
d2 = {"key1": "x2", "key3": "y2", "key4": "w1"}

common_keys = d1.keys() & d2.keys()

d1 = {k: d1[k] for k in common_keys}
d2 = {k: d2[k] for k in common_keys}

print(d1)
print(d2)

Prints:

{'key1': 'x1', 'key4': 'z1'}
{'key1': 'x2', 'key4': 'w1'}