map array of parts to string via regex in deno (typescript)

April 4, 2023

I used a regex "(.*?)" to get all the things between quotation marks in a string. After running the operations on the array provided by exec(), I now have an array of these slices to put back into the string. How might I map this array back to the string using the regex?

I know about replacing them all with one specific value, but I’m not sure how to do it with an array. Perhaps there’s some kind of map() that takes a function that I can use to pop() values from the array?

I’m quite new to Deno and JS in general (coming from a more low-level background), so sorry if I just missed a doc or something.

>Solution :

Using .replace with a replacement function is the easiest way to accomplish what you want.

const html = `
    <a href="https://example.com/foo">foo</a>
    <div></div>
    <a href="https://example.net/foo">foo</a>
`;

const result = html.replace(/"(.*?)"/g, (match, group) => {
    return `"https://example.org/?url=${group}"`;
});

console.log(result);

You can also use a replace string with $n replacement pattern

 const html = `
        <a href="https://example.com/foo">foo</a>
        <div></div>
        <a href="https://example.net/bar">bar</a>
 `;
 
const result = html.replace(/"(.*?)"/g, `"https://example.org/?url=$1"`);

console.log(result);