ORACLE SQL number of customers who have ordered something on a date

I have 2 tables involved, the "customers" table and the "orders" table.

The "customers" table has the following columns:

Customerid, companyname, contactname, contactittle, addresses, city

The "Orders" table has the following columns:

orderid, customerid, employeeid, orderdate, shippeddate, shipname

I have to do where the number of customers who have ordered a product in the year 97 comes out.

It should be something like

Number of clients 20

I have tried the following code, but I think it is wrong for the following two reasons

1-I think that like '%97%' may cause errors in the future

2-For some reason it takes me the number of orders that have been made, not the number of customers

SELECT DISTINCT(COUNT (companyname))as Numero_CLIENTES
FROM customers JOIN orders ON customers.customerid=orders.customerid
WHERE orderdate like '%97%'

>Solution :

Sample data:

SQL> with
  2  customers (customerid) as
  3    (select 1 from dual union all
  4     select 2 from dual union all
  5     select 3 from dual
  6    ),
  7  orders (orderid, customerid, orderdate) as
  8    (select 100, 1, date '1997-12-02' from dual union all  --> customer 1 counts as "1"
  9     select 101, 1, date '2000-03-28' from dual union all
 10     select 102, 2, date '1997-05-29' from dual union all  --> customer 2 counts as "1" as well
 11     select 103, 2, date '1997-06-12' from dual            --> because both orders were made in 1997
 12    )

Query:

 13  select count(distinct c.customerid) numero_clientes
 14  from customers c join orders o on o.customerid = c.customerid
 15  where extract(year from o.orderdate) = 1997;

NUMERO_CLIENTES
---------------
              2

SQL>