Python "Guess the number" game

this is my first post in StackOverFlow and I’m sure. that I can find for 100% percent an answer for it, but I’d really like to start my adventure with programming and know that this community might help me with it.

My q’s is:

I wrote that first piece of code but I’d like to add here a function where the user writes the guess number bigger than the first one.

I am troubled with adding the additional function "if" for this situation – I do understand that it wouldn’t suppose to be if, but "elif".
Is anyone has any idea how to suppose to look-alike??

Thanks for any advice

top_range = input("Write a number bigger then 0: ")
if top_range.isdigit() or top_range[0] == "-":
 top_range = int(top_range)
 if top_range <= 0:
     print('Write a number bigger then 0')
     quit()
else:
 print('Write a number bot a word')
 quit()
 random_number = random.randint(0, top_range)
guesses = 0
while True:
 guesses += 1
 user_guess = input("Guess the number : ")
 if user_guess.isdigit():
         user_guess = int(user_guess)
 else:  
     print('Write another number.')
     continue    
 if user_guess == random_number:
     print('You did it!')
     break
 else:
     if user_guess < random_number:
       print('The number is bigger then that')
     else:
       print('The number is smaller than that')        
print('You did it in', guesses, "guesses!")```

>Solution :

Add a first if, then use elif for the other choices. I’ve also simplify a bit the first if

while True:
    guesses += 1
    user_guess = input("Guess the number : ")
    if not user_guess.isdigit():
        print('Write another number.')
        continue

    user_guess = int(user_guess)

    if user_guess > top_range:
        print("That is higher than top range, try again")
    elif user_guess == random_number:
        print('You did it!')
        break
    elif user_guess < random_number:
        print('The number is bigger then that, try again')
    else:
        print('The number is smaller than that, try again')