Imagine this "sneaky" python code:
>>> 1 == 2 < 3
False
According to Python documentation all of the operators in, not in, is, is not, <, <=, >, >=, !=, == have the same priority, but what happens here seems contradictory.
I get even weirder results after experimenting:
>>> (1 == 2) < 3
True
>>> 1 == (2 < 3)
True
What is going on?
(Note)
>>> True == 1
True
>>> True == 2
False
>>> False == 0
True
>>> False == -1
False
Boolean type is a subclass of int and True represents 1 and False represents 0.
This is likely an implementation detail and may differ from version to version, so I’m mostly interested in python 3.10.
>Solution :
Python allows you to chain conditions, it combines them with and. So
1 == 2 < 3
is equivalent to
1 == 2 and 2 < 3
This is most useful for chains of inequalities, e.g. 1 < x < 10 will be true if x is between 1 and 10.
WHen you add parentheses, it’s not a chain any more. So
(1 == 2) < 3
is equivalent to
False < 3
True and False are equivalent to 0 and 1, so False < 3 is the same as 0 < 3, which is True.
Similarly,
1 == (2 < 3)
is equivalent to
1 == True
which is equivalent to
1 == 1
which is obviously True.