Re Regular expression operations, remove periods?

May 5, 2022

I’m working with a function I made to split this sample line below to remove the standalone numerical values (123), however it’s also removing the trailing numbers which I need. I also can’t figure out how to remove the "0.0"

ABC/0.0/123/TT1/1TT//

cleaned_data = []
def split_lines(lines, delimiter, remove = '[0-9]+$'):
  for line in lines:
    tokens = line.split(delimiter)
    tokens = [re.sub(remove, "", token) for token in tokens]
    clean_list = list(filter(lambda e:e.strip(), tokens))
    cleaned_data.append(clean_list)
    print(clean_list)
split_lines(lines, "/")

What’s coming out now is below, notice the 0. and "TT" that’s missing the trailing 1.

[ABC], [0.], [TT], [1TT]

>Solution :

Try including the start of line anchor (^) as well.

cleaned_data = []
def split_lines(lines, delimiter, remove = '^[0-9.]+$'):
  for line in lines:
    tokens = line.split(delimiter)
    tokens = [re.sub(remove, "", token) for token in tokens]
    clean_list = list(filter(lambda e:e.strip(), tokens))
    cleaned_data.append(clean_list)
    print(clean_list)
split_lines(lines, "/")

I simply changed the default value of the remove parameter to ‘^[0-9.]+$’ which only matches if the entire search string is numbers (or a period).