Remove specific lines of a regex pattern targets

I have a list like following:

ABC
5
0
gdfgdfg
-----------
GHN
3
0
ffffffff
fffff
ffff
trte
-------------
H
1
0
----------------

I would like to delete lines where the line above them starts with a character, and the line below them starts and ends with a zero.
for example above list must convert to following:

ABC

0
gdfgdfg
-----------
GHN

0
ffffffff
fffff
ffff
trte
-------------
H

0
----------------

following regex can select target lines but I don’t know how to remove second lines of regex:

^(.+\S)$\R^(\d+)$\R^(0)$

note that second lines must include only a single number between 0-9

>Solution :

You can use

^(.*\S\R)(\d)(\R0)$

Replace with $1$3. See the regex demo.

It is the same as find ^(.*\S\R)\d(\R0)$ and replace with $1$2 but I kept the third group just in case you need it.

Details

• ^ – start of a line
• (.*\S\R) – Group 1: a line ending with a non-whitespace char and a line break (sequence)
• (\d) – Group 2: a digit between 0 and 9
• (\R0) – Group 3: a line break (sequence) and 0
• $ – end of a line.

See the demo screenshot: