Sort list of dict based on value present in another list in python

I have following list of dict:

list_of_dict = [
{'vectorName': 'draw', 'value': 52.06}, 
{'vectorName': 'c_percentage', 'value': 15.24}, 
{'vectorName': 'o_temprature', 'value': 1578.0}
]

I have another list of keywords:

list_of_keywords = ['draw', 'o_temprature', 'name', 'c_percentage', 'data']

I want to sort the list of dict based on list of keywords and then get list of values in ordered format :

[512.06, 1578.0, 15.24]

I am trying following peice of code but not working (getting list_of_sorted_dict as None).

list_of_sorted_dict = list_of_dict.sort(key=lambda x: list_of_keywords.index(x["vectorName"]))

Kindly help

>Solution :

Your approach is correct, but the list.sort() is an in-place sorting method, which means that it sorts list_of_dict and returns None. If you want a separate sorted variable, you can do the following.

list_of_sorted_dict = sorted(list_of_dict, key=lambda x: list_of_keywords.index(x["vectorName"]))