Trying to pull all the values that matches the key into one key

May 30, 2022

I’ve been trying to simply just pull all the values that matches the key into one key. I can’t wrap my head around on how to do this. Please help.

list_dir = ['192586_Sample_010_Test.pdf', '192586_Sample_020_Test.pdf', '192586_Sample_050_Test.pdf', '192120_Sample_020_Test.pdf', '192120_Sample_050_Test.pdf', '192163_Sample_010_Test.pdf', '192163_Sample_020_Test.pdf', '192145_Sample_010_Test.pdf', '192145_Sample_020_Test.pdf', '192145_Sample_050_Test.pdf', '192051_Sample_010_Test.pdf', '192051_Sample_020_Test.pdf', '192051_Sample_050_Test.pdf']
dict = {}

match = []
for i in list_dir:
    match.append((i.split("_", 1)[-2]))

for i in match:
    for x in list_dir:
        if i in x:
            dict[i] = list_dir

print(dict)

Output I’m looking for is

{'192586': '192586_Sample_010_Test.pdf', '192586_Sample_020_Test.pdf', '192586_Sample_050_Test.pdf', 
'192120': '192120_Sample_020_Test.pdf', '192120_Sample_050_Test.pdf', 
'192163': '192163_Sample_010_Test.pdf', '192163_Sample_020_Test.pdf', 
'192145': '192145_Sample_010_Test.pdf', '192145_Sample_020_Test.pdf', '192145_Sample_050_Test.pdf', 
'192051': '192051_Sample_010_Test.pdf', '192051_Sample_020_Test.pdf', '192051_Sample_050_Test.pdf'}

>Solution :

Just extract the key from the string and check if it’s in the dict or not. If so append to the list otherwise create a new list.

Like this:

dict = {}

for i in list_dir:
    key = i.split("_")[0]
    
    if key in dict:
        dict[key].append(i)
    else:
        dict[key] = [i]

print(dict)