Using && operator in javascript return statement

I am learning javascript and I was applying the filters in javascript code, In below code, is there any possibility to improvise this code ? i was hoping if someone could tell me to how to use only one variable to store result of ages which are greater than 18 and less than 18. is there possibilty to use && operator in single return statement ? So that in final result I can show the data as

Voters under 18,21,24,30,32 category can vote.
Voters under 10,15 category cannot vote

//Code

const ages = [10, 15, 18, 21, 24, 30, 32];
const ageResultabove = ages.filter((ageabove) => {
  return ageabove >= 18;
});
const ageResultbelow = ages.filter((ageabelow) => {
  return ageabelow < 18;
});
console.log(`Voters under ${ageResultabove} category can vote`);
console.log(`Voters under ${ageResultbelow} category cannot vote`);

Result should be like this
Voters under 18,21,24,30,32 category can vote.
Voters under 10,15 category cannot vote

>Solution :

You could take a function for checking adult ages and group by this result with true and false in a single loop.

const
    ages = [10, 15, 18, 21, 24, 30, 32],
    isAdult = age => age >= 18,
    result = ages.reduce((accumulator, age) => {
        accumulator[isAdult(age)].push(age);
        return accumulator
    }, { true: [], false: [] });

console.log(`Voters under ${result.true.join(', ')} category can vote`);
console.log(`Voters under ${result.false.join(', ')} category cannot vote`);