What is the best way to remove a specificed phrase from a string?

October 1, 2022

So if I have a string: let foo = "test/string/plz", and I wanted to remove "string", what would be the best way to do so? I have devised a solution below:

fn delete_phrase(input: String, find: String) -> String{
    let mut temp = input.clone();
    
    if input.contains(&find){
        let index = input.find(&find);
        for _i in 0..find.len(){
            temp.remove(index.unwrap());
        }
    }

    return temp.to_string();
}

Is there a better way to do this?

>Solution :

We can use if let to greatly reduce the code to just an if-else statement:

fn delete_phrase(input: String, find: String) -> String {
    if let Some(index) = input.find(&find) {
        let left = &input[0..index];
        let right = &input[index + find.len()..];
        
        return [left, right].concat();
    } else {
        return input;
    }
}

Then, we’re taking @FilipeRodrigues’s suggestion and using slices to get everything before and after the match. After that, we just need to join the slices together.

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