Iterate through nested arrays of objects with an undetermined number of children node levels

In a multi-node tree, when I add a new row, I need to get the reference of that row, by its id, to fire the rowclick event programmatically.

In the following example, if I add the row with id 9, how to iterate through the tree to this node.

Note: children of children nodes are unlimited (for example: parent-children-children-children-children-children… )

Tree example

let data = [{
    "id": 1,
    "name": "parent 1"
}, {
    "id": 2,
    "name": " parent 2",
    "children": [{
        "id": 5,
        "name": "parent-children 5",
    },{
        "id": 6,
        "name": "parent-children 6",
        "children": [{
            "id": 7,
            "name": "parent-children-children 7",
        },{
            "id": 8,
            "name": "parent-children-children 8",
            "children": [{
                "id": 9,
                "name": "parent-children-children-children 9",
            },{
                "id": 10,
                "name": "parent-children-children-children 10",
            }]
        }]
    }]
}, {
    "id": 3,
    "name": "parent 3"
}, {
    "id": 4,
    "name": "parent 4"
}]

Iteration on levels one and two of the nodes

getItemRow(id){
    //If is a parent node
    let myItem = this.parents.find(parent => parent.id === id);
    if(myItem !== undefined){ return myItem }

    //If is a second level children node (parent-children)
    this.parents.forEach(function(parent){
        let child = parent.children.find(child => child.id === id);
        if(child !== undefined){ return child }

    });
}

>Solution :

We can recursively search all nodes until we find the match:

getItemRow(id){
    return findNodeWithId(id, this.parents)
}

findNodeWithId(id, rootArr) {
  for (let el of rootArr) {
    if (el.id === id) {
      return el
    }
    if (el.children) {
        const idFoundInChildren = findNodeWithId(id, el.children)
        if (idFoundInChildren !== null) {
          return idFoundInChildren
        }
    }
  }
  return null
}