recursive calling to print list of numbers

I’m trying to sort an array and print the output recursively until the array is = [0,0,0,0,0] but it only prints [3,2,1,0,0] ,,,,, this is what i wrote can you help to fix this isuee ,, still learning
the answer should be

[4 3 2 1 0 0]
[3 2 1 0 0 0]
[2 1 0 0 0 0]
[1 0 0 0 0 0]
[0 0 0 0 0 0]





numbers=[5,4,3,2,1,1]
numbers.sort()

numbers.sort(reverse=True)

print('List sorted: ', numbers)


def list_arrays(numb):
level=numbers[0]
if len(numbers)-1 < level:
    return 0
    
else:
        numbers.pop(0);
        print(numbers)
        for i in range(len(numbers)):
            numbers[i] -= 1
        
        print(numbers)
        #list_arrays(numbers)
        
        


if __name__=='__main__':
    list_arrays(numbers)

>Solution :

In another comment you asked to remove all zeroes. Perhaps this is the solution you are looking for –

def run(t):
  while(t):
    yield t
    t = [x - 1 for x in t if x > 1]

mylist = [5,4,3,2,1,1]
for t in run(mylist):
  print(t)

[5, 4, 3, 2, 1, 1]
[4, 3, 2, 1]
[3, 2, 1]
[2, 1]
[1]

Or gather all lines in a single array using list –

mylist = [5,4,3,2,1,1]
print(list(run(mylist)))

[
  [5, 4, 3, 2, 1, 1],
  [4, 3, 2, 1],
  [3, 2, 1],
  [2, 1],
  [1]
]