We have array with objects:
let store = [
{
id: 1,
name: "store1",
items: {
pen: 0,
apple: 1,
chocolate: 0
}
},
{
id: 2,
name: "store2",
items: {
pen: 0,
apple: 0,
chocolate: 0
}
},
{
id: 3,
name: "store3",
items: {
pen: 0,
apple: 1,
chocolate: 1
}
},
]
and the criteria is: ["apple", "chocolate"].
We have to find the objects where meets the criteria.lenght > 0 and give back a boolean true/false
This is how I tried
store.filter(store => criteria.forEach(i => store.items[i] > 0))
>Solution :
You could filter by checking all criteria with Array#every.
const
stores = [{ id: 1, name: "store1", items: { pen: 0, apple: 1, chocolate: 0 } }, { id: 2, name: "store2", items: { pen: 0, apple: 0, chocolate: 0 } }, { id: 3, name: "store3", items: { pen: 0, apple: 1, chocolate: 1 } }],
criteria = ["apple", "chocolate"],
result = stores.filter(store =>
criteria.every(criterion => store.items[criterion] > 0)
);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }If you want all stores if at least on criterion is true, take Array#some
const
stores = [{ id: 1, name: "store1", items: { pen: 0, apple: 1, chocolate: 0 } }, { id: 2, name: "store2", items: { pen: 0, apple: 0, chocolate: 0 } }, { id: 3, name: "store3", items: { pen: 0, apple: 1, chocolate: 1 } }],
criteria = ["apple", "chocolate"],
result = stores.filter(store =>
criteria.some(criterion => store.items[criterion] > 0)
);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }