I have a comparison to make between two lists, and for each item found, I have to return a property from the second list, I would like to do it via LINQ. I have this class: class Table { private int hexToInt = 0; private string data = string.Empty; public int HexToInt { get =>… Read More How to compare 2 objects and return a property of the second object that is not in the comparison

I want to compare two lists of the same length by their elements with an OR. >>> [0,0,1,1,0] or [1,1,0,1,0] [0, 0, 1, 1, 0] I want the outcome to be [1,1,1,1,0] How can I achieve the desired comparison? >Solution : You can use zip() function is used to iterate over corresponding elements of both… Read More Compare two lists elementwise with OR

I am trying to assess in a sales database whether the # of advertisements has changed. The example dataframe I am using is as such: df = pd.DataFrame({"offer-id": [1,1,2,2,3,4,5], "date": ["2024-02-10","2024-02-11","2024-02-10","2024-02-11","2024-02-11","2024-02-11","2024-02-10"], "price": [30,10,30,30,20,25,20]}) And looks like the below: I am now trying to get the # of items that were sold or newly added (I… Read More How to group by and find new or disappearing items

Please explain why this code is crashing? #include <vector> #include <cassert> #include <algorithm> int main() { std::vector<int> vt = {1,2,3,4}; assert(std::is_sorted(vt.begin(), vt.end(), [](const auto& a, const auto& b){ return true;})); } https://godbolt.org/ >Solution : The comparison function (the lambda expression) is incorrect. It returns always true for vt[i] < vt[j] and for vt[j] < vt[i].… Read More std::is_sorted return false when lambda return always true

Would doing the following be faster or slower than just an if statement? mult = x or y # Assuming python considers something # being "0" as false and something being 1 or higher # (or -1 and lower) as true mult = (x/x) or (y/y) # This is in the case Python doesn’t do… Read More Is a comparison or if statement faster

I have 2 arrays with objects With car brands const brands = [ { id: 1, name: "Mercedes Benz", bodyType: [1, 3] }, { id: 2, name: "Audi", bodyType: [1, 2] }, { id: 3, name: "BMW", bodyType: [3, 4] }, { id: 4, name: "Mazda", bodyType: [1, 2, 4] } ]; With body types… Read More Stuck with comparison arrays with objects which has IDs

I am working in a C code for school, the program is supposed to extract an array N of float values and determinate the pairs with the shortest distance between them; when there is only one closest pair of numbers the code prints it properly, however, when there are more (2 or +), is simply… Read More Code do not print values when are repeated

For my problem, I have 4 lists, each containing 10,000 elements. Let the lists be a, b, c, d. I can calculate Probablity(a<b) by just performing mean operation mean(a<b). If I understand correctly, it compares each of the 10,000 elements in a and b in order and tells me for how many elements a<b holds… Read More Comparisons of more than two lists in R

if x[3] > y and x[4] > y and x[5] > y and x[6] > y and x[7] > y and x[8] > y: … Do U have a more elegant method to compare it? actually, I have to compare one value with 30 values in the array, do U know a better way to… Read More How to make a comparison of part of an array with one value

So basically I am trying to compare two lists to see if they hold the same value at the same index at any point. If they do I return the index, if they do not, I return -1. ` Dlist = [17,13,10,6,2] Ilist = [5,9,10,15,18] def seqsearch(DS,IS): for i in range(len(DS)-1): found = False if… Read More Check to see if two lists have the same value at the same index, if so return the index. If not return -1