# Comparisons of more than two lists in R

For my problem, I have 4 lists, each containing 10,000 elements. Let the lists be a, b, c, d. I can calculate Probablity(a<b) by just performing mean operation mean(a<b). If I understand correctly, it compares each of the 10,000 elements in a and b in order and tells me for how many elements a<b holds… Read More Comparisons of more than two lists in R