I have a list of values, and a list of dictionaries such as: my_values = ["A", "B", "C"] my_dicts = [{…}, {…}, {…}] I would like to unpack my values into my dictionaries so that the value in position n goes in the nth dictionary, such as: my_new_dicts = [{"value": "A", …}, {"value": "B", …},… Read More Add element of list in dictionary of other list at the same index

I have the following lists: mylist1 = ["peru", "germany", "japan"] mylist2 = [["lima","cusco"], ["berlin","munich"], ["tokyo"]] mylist3=[[1,2],[3,4],[5]] and I want to print peru lima 1 cusco 2 germany berlin 3 munich 4 japan tokyo 5 One zip command looks like: list=list(zip(mylist1,mylist2,mylist3)) for country,cities,nums in list: print(country) for city in cities: print(city) for num in nums: print(num)… Read More How to create a zip of zip of a list in python. I need it for a double for loop

I am having following code in AWS lambda to zip S3 files import zipfile import boto3 from io import BytesIO def lambda_handler(event, context): in_bucket = ‘in_bucket’ in_key = ‘test/run_id=123/’ out_bucket = ‘out_bucket’ out_key = ‘test/zip_output/model.zip’ createZipFileStream(in_bucket, in_key, out_bucket, out_key) def create_zip(in_bucket, in_key, out_bucket, out_key): s3 = boto3.resource(‘s3’) bucket = s3.Bucket(in_bucket) files_collection = bucket.objects.filter(Prefix=in_key).all() archive =… Read More AWS S3 – Zip only file objects not path

I have a zipped folder : folder.zip, the zip contains file1 and file2. I want to unzip file1 without unzipping folder.zip (Like what we can do using WinRaR). I want to be able to do this scenario using command line : open (Without unzipping) folder.zip and display content Find file1 inside folder.zip Unzip file1 Get… Read More How to unzip a file inside a zipped folder without unzipping the folder.zip using command line?

Current code: reps = [‘x 5’, ‘x 5’, ‘x 3’, ‘x 5’, ‘x 5’, ‘x 5+’] b = [90, 122, 135, 146, 168, 191] print(str(list(zip(b,reps))).replace(‘,’,”)) here is the current output: [(90 ‘x 5’) (112 ‘x 5’) (135 ‘x 3’) (146 ‘x 5’) (168 ‘x 5’) (191 ‘x 5+’)] here is my goal output: [(90 x… Read More How do I use zip print on a list of strings in python without it returning with quotations surrounding them?

Is there any way that while using the ZIP function we can provide some default value to parallel elements which are not present and still print the entire stuff? eg, for the below code 6 from list a getting missed but I don’t want that to happen a = [1,2,4,6] b = [[1,3],[4,7],[6,1]] for a,(b,c)… Read More how to use zip efficiently to iterate parallelly in multiple lists

I have a zip file which contains a text file(with millions of lines). I need to read line by line, apply some transformations to each line and write to a new file and zip it. with zipfile.ZipFile("orginal.zip") as zf, zipfile.ZipFile("new.zip", "w") as new_zip:
 with io.TextIOWrapper(zf.open("orginal_file.txt"), encoding="UTF-8") as fp, open("new.txt", "w") as new_txt:
 for line in… Read More Read contents from zipfile, apply transformation and write to new zip file in Python